2007-12-03 17:04:38 · 6 answers · asked by PrestigesGlow 1 in Science & Mathematics ➔ Mathematics
(x + y) / 2 = m
x + y = 2m
(x + y + z) / 3 = (2m + 2m) / 3 = 4m / 3
Average = 4m / 3
2007-12-03 20:46:32 · answer #1 · answered by Como 7 · 0⤊ 0⤋
average of x, y and z
= (x + y + z)/3 = (2m + 2m)/3 = 4m/3
2007-12-04 01:12:45 · answer #2 · answered by sv 7 · 0⤊ 0⤋
total of x and m is 2m
total of x y and z is 2m+2m=4m
average of all 3 is 4m/3
2007-12-04 01:07:31 · answer #3 · answered by someone else 7 · 0⤊ 0⤋
The average of 2 quantities is (x+y)/2. The average of 3 quantities is (x+y+z)/3. So, if the average of x and y is m, then x+y=2m
x+y+z=4m
and the average is 4/3 m
2007-12-04 01:07:45 · answer #4 · answered by Anonymous · 0⤊ 0⤋
(x+y)/2=m ; x+y=2m
z=2m=2*((x+y)/2)=x+y
(x+y+z)/3 =?
(x+y+z)/3=(x+y+(x+y))/3=(2m+2m)/3=4m/3
2007-12-04 01:12:14 · answer #5 · answered by goodi 3 · 0⤊ 0⤋
(2x + 2y)/3
2007-12-04 01:13:24 · answer #6 · answered by catsfanj 3 · 0⤊ 0⤋