1/e - 1/f = 1/g solve for f incase you cannot tell, these are in fraction form
2007-12-03 16:51:58 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
multiply f on both sides
f/e -1=f/g
f/e -f/g=1
f(1/e -1/g)=1
f=1/(1/e-1/g)
f=1/[(g-e)/eg]
f=eg/(g-e)
2007-12-03 16:55:32 · answer #1 · answered by someone else 7 · 2⤊ 0⤋
1/f = 1/e - 1/g
multipy both sides by f
1 = f(1/e - 1/g)
f = 1/(1/e -1/g)
f = (eg)/(g-e)
you cannot invert both sides of an equation easily unless there is only one term on each side !!!
2007-12-03 17:00:31 · answer #2 · answered by ASHVIR S 1 · 1⤊ 0⤋
this is the first equation with 3 anonymous i've ever seen, and i think it's kinda impossible to solve it, with two anonymous we can do it as a function, 1 anonymous piece of cake :)
2007-12-03 16:56:28 · answer #3 · answered by Med 2 · 0⤊ 0⤋
f = ( - e * g) / (e - g)
Don't listen to anyone who says different.
2007-12-03 16:56:09 · answer #4 · answered by wings4shoes 6 · 0⤊ 1⤋
the answer is do it urself u lazy bum
2007-12-03 16:55:00 · answer #5 · answered by coolkid 2 · 0⤊ 3⤋
fg - eg = ef
f (g - e) = eg
f = (eg) / (g - e)
2007-12-03 21:34:53 · answer #6 · answered by Como 7 · 0⤊ 0⤋
g=e-f then i am not sure from there
2007-12-03 16:54:01 · answer #7 · answered by steve 2 · 0⤊ 2⤋
f = e-g
2007-12-03 16:53:58 · answer #8 · answered by XPEH BAM 3 · 0⤊ 2⤋
obviousely f=e-g.
2007-12-03 16:55:45 · answer #9 · answered by pyro079 2 · 0⤊ 1⤋
f=eg/(g-e)
2007-12-03 16:57:50 · answer #10 · answered by Anonymous · 0⤊ 0⤋