find x
2007-12-03 16:37:49 · 5 answers · asked by Small Victories 4 in Science & Mathematics ➔ Mathematics
x²-4x+6=0
It's already in the form
ax²+bx+c=0
a=1, b= -4, c=6
The Quadratic Formula
x = {-(b) ±√[(b)² - 4(a)(c)]}/[2(a)]
Substituting
x = {-(-4) ±√[(-4)² - 4(1)(6)]}/[2(1)]
x = {4 ±√[16 - 24]}/2
x = {4 ±√[-8]}/2
x = {4 ± i√[8]}/2
x = 2 ± (i)√2
2007-12-03 16:50:51 · answer #1 · answered by gugliamo00 7 · 1⤊ 1⤋
x^2-4x+4-4+6=0 using completing the square
(x-2)^2=-2
x-2=sqrt-2
x=2+-isqrt2
2007-12-03 16:44:31 · answer #2 · answered by someone else 7 · 2⤊ 1⤋
x = [ 4 ± â(16 - 24) ] / 2
x = [ 4 ± â ( - 8 ) ] / 2
x = [ 4 ± i 2 â2 ] / 2
x = 2 ± i â 2
2007-12-04 00:27:48 · answer #3 · answered by Como 7 · 2⤊ 1⤋
Use quadratic formula, very easy.
You get negative under square root so that anaswer ir no real numbers.
2007-12-03 16:42:17 · answer #4 · answered by GetDownWithThe$ickness 4 · 1⤊ 1⤋
2 +/- i sqrt(2)
2007-12-03 16:44:50 · answer #5 · answered by Anonymous · 2⤊ 1⤋