Physics question?

Question

a 615kg racing car completes one lap in 14.3 s around a circular track with a radius of 50.0 m. The car moves at a constant speed. What is the Acceleration of the car? What force must the track exert on the tires to produce this acceleration? write the equation you use for it too....

Answer 1

a = v^2/r = (C/T)^2/r = (2πr/T)^2/r = 4π^2r/T^2
a = 4π^2(50.0 m) / (14.3 s)^2
a ≈ 9.652897 m/s^2 9.652897 m/s^2
F = ma = 4π^2mr/T^2
F ≈ 4π^2(615 kg)(50.0 m) / (14.3 s)^2
F ≈ 5,936.532 N ≈ 5,940 N

Answer 2

well centripetal acceleration equals v^2/r and the net centripetal force must equal m*centripetal acceleration where m is mass of the object.