2007-12-03 14:04:28 · 5 answers · asked by funcouple169 1 in Science & Mathematics ➔ Mathematics
First write it like this:
log2(x) - log8(x) = 4
loga(x)/loga(b) = logb(x)
So we can replace log8(x) with log2(x)/log2(8)
log2(x) - log2(x)/log2(8) = 4
log2(8) = 3
so,
log2(x) - log2(x)/3 = 4
2/3(log2(x)) = 4
log2(x) = 6
x = 2^6 = 64
2007-12-03 14:21:56 · answer #1 · answered by Anonymous · 0⤊ 0⤋
x=64
Log2 (64) = 6
Log8 (64) = 2
4=4
log2 x = log8 x +4 -------change base on log8
log2 x = log2 x/log2 8 + 4 ---------log2 8 = 3
2/3 log2 x = 4
log2 x = 6
x = 2^6 = 64
2007-12-03 22:16:19 · answer #2 · answered by DANIEL G 6 · 0⤊ 0⤋
log2(x)=log8(x)+4
log2=(log8(x)+4)/x
log2=( (log8(x) ) / x ) + (4/x)
log2= log8 + (4/x)
log2 - log8 = 4/x
x= 4 / (log2 - log8)
2007-12-03 22:12:01 · answer #3 · answered by originalquene 4 · 0⤊ 2⤋
Change log 8(x) to log 2 (x)
Then use log a -log b = log(a/b) = 2^2
Answer pops right out.
2007-12-03 22:19:44 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋
That answer woudl be 334@2power
2007-12-03 22:07:17 · answer #5 · answered by Lasha 1 · 0⤊ 3⤋