f ( x ) = ( 1 + x ² )^(- 1)
f `(x) = (- 1)( 1 + x ² )^(- 2) ( 2 x )
f `(x) = (- 2 x ) / ( 1 + x ² ) ²
2007-12-05 06:16:44
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answer #1
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answered by Como 7
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first if you want to you can rewrite it as (1+x^2)^-1 now by the power rule you see that this becomes -1(1+x^2)^-2 and by the chain rule we must multiply the result by the derivative of the "inside" which is 2x, now we should have -1(1+x^2)^-2 *2x. Now rewriting with positive exponents we have -2x/(1+x^2)^2
2007-12-03 13:49:11
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answer #2
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answered by Anonymous
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Write it as (1+x^2)^(-1)
This should make it easier. Now you can just use the power rule and chain rule
2007-12-03 13:40:52
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answer #3
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answered by Demiurge42 7
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f(x) = (x^2+1)^(-1)
= -(x^2+1)^(-2) * (2x)
= (2x)/(x^2+1)^2
2007-12-03 13:48:07
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answer #4
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answered by John 4
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use the differentiation method if you want
but if you'll going to rewrite it as
f(x)=(1-x^2)^-1
you can use the power rule.it is lot more easier i think.
2007-12-03 14:13:50
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answer #5
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answered by harry 1
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-2x/(1 + x²)²
2007-12-03 13:41:08
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answer #6
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answered by Joe L 5
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0/(0
+2X)
2007-12-03 13:44:04
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answer #7
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answered by samuel a 1
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