need help if my answers are right for math..?

Question

1. write a quadratic equation with -4 and 6
= i put...x^2+2x-24

2. solve by completing the square. 2x^2+x-6=0
i put=

3.Solve x^2=12
: im not sure how to do this

4. (x-1)^2=9
: i got x=12 x= -4

5. find vertex, x and y coordinate x^2-2x-8
v- (1,-9) y(0,-8) x(1,0)

6. 2x^2-13x=7use quadratic formula
: i got 4.6 or -0.3

7. x^2+x-6<0
: i got (x+3) (x-2)

Answer 1

1. (x+4)(x-6) = x^2 -2x -24 =0
2. 2x^2 +x = 6
x^2 +.5x = 3
x^2 +.5x + .0625. = 6.0625
(x+.25)^2 = sqrt(6.0625)
x+.25 = +/-sqrt(6.0625)
x = -.25 +/-sqrt(6.0625)

x^2 =12
x = =/- sqrt(12) = +/- 2sqrt(3)

(x-1)^2 = 9
x-1 = +/-3
x = 1 +/- 3
x = 4 or -2

y = x^2 -2x -8
y+8 = x^2 -2x
y+8 +1 = x^2-2x +1
y+9 = (x-1)^2
Vertex at (1,-9)

x = [13 +/- sqrt(13^2-4(2)(-7))]/(2*2)
x = [12 +/- sqrt(225)]/4
x = [12 +/- 15]/4
x = 27/4 or -3/4

x> -3 and x < 2

Answer 2

x^2-2x-24=0
move your c term to the other side of the equation
x^2-2x=24
take (b/2)^2, add to both sides of the equation thus
completing the square would give you
x^2-2x+1=24+1
this creates a perfect square
(x-1)^2=5^2
take the square root of each side giving you
x-1=+/-5
then x= -5+1 and 5+1
which is -4 and six
your mistake is that you completed the square wrong. The formula is (b/2)^2 to complete the square
I hope this helped.
Darlene