QUADRATIC HELp!?

Question

alright heres my problems i need them ASAP

a) 12n(squared)=60
b) 3y(squared)-144=30
c)2(x-5)(squared)-10=24

the sum of a number and 5 is qquared the result is 81 whar are the numbers that make this statemaent true?

5 times the square of the sum of two numbes is equal to 45 what are the numbers that make this statement true?

Answer 1

12n^2 = 60
n^2 = 5
n = +/- sqrt(5)

3y^2 - 144 = 30
3y^2 = 174
y^2 = 58
y = +/- sqrt(58)

2(x-5)^2 - 10 = 24
2(x-5)^2 = 34
(x-5)^2 = 17
x-5 = +/- sqrt(17)
x = 5 +/- sqrt(17)

(x-5)^2 = 81
x-5 = +/- 9
x = 14 or -4

5(x+y)^2 = 45
(x+y)^2 = 9
x+y = +/- 3
any pair of numbers that satisfy the above

Answer 2

a) First, you have 12n^2-60.
Divide by 12 to get n^2=5.
Take the square root to get n=+or-sqrt(5)
b) 3y^2-144=30
Move 144 to the other side of the equation to get 3y^2=174
Divide by 3 to get y^2=58
Take the square root to get y=+or-sqrt(58)
c) 2(x-5)^2-10=24
Move 10 to the other side of the equation to get 2(x-5)^2=34
Divide by 2 to get (x-5)^2=17
Take the square root to get x-5=+or-sqrt(17)
Finally, add 5 to get x=5+or-sqrt(17)
d) (x+5)^2=81
Take the square root to get x+5=9,-9
Subtract 5 to get x=4,-14
e)5(x+y)^2=45
Divide by 5 to get (x+y)^2=9
Take the square root to get x+y=3 or -3
These are all the numbers that satisfy the equation.