Physics - Rope & Pulley?

Question

Ok, I'm at a loss for how to figure this out.

There's a rope and pulley system with two blocks. The first block (M1) is attached to a rope above the ground. The second (M2) is on a ramp incline.

Ramp angle is at 20º
Ramp is high enough for M1 to fall 4 meters before hitting ground.
Mass M2 is 100 kg

Static coefficients of M2 are:
Static friction = 0.35
Kinetic friction = 0.30.

Also assume we have an "ideal" rope (no mass and doesn't stretch) and "ideal" pulley (no mass or friction).

So, my question: What does the mass of M1 have to be in order for M2 to move up the ramp? In addition, what is the velocity of M2 when M1 hits the ground?

Equations, descriptions, ANYTHING will help at this point. Thanks!

Answer 1

May I assume that the rope is parallel to the slope on the m2 side and then hangs over the pulley vertically supporting m1? I yes then

The force pushing the m2 down with m2 absent is

F= Fd - f
F= m2g(sin(20) - u cos(20))

to reverse the motion using m1 we have

F= m2g(sin(20)+ u cos(20))

then also
since F=m1g
m1g=F= m2g(sin(20)+ u cos(20))
m1=m2(sin(20)+ u cos(20))
actually
m1>m2(sin(20)+ u cos(20))

Since they move as a system
if m1>m2(sin(20)+ u cos(20))
F'=a(m1+m2)

then
V=at

if m1=m2(sin(20)+ u cos(20))

V=constant