2007-12-03 10:59:28 · 7 answers · asked by polarbeardude 1 in Science & Mathematics ➔ Mathematics
I = ∫ 1 - 2x dx
I = x - x² + C
2007-12-04 09:39:36 · answer #1 · answered by Como 7 · 2⤊ 1⤋
x-x^2
2007-12-03 19:04:18 · answer #2 · answered by slovakmath 3 · 0⤊ 0⤋
x - x^2
To find an integral, you take each term and increase the power of x by 1 and divide by the new power.
1 has power zero so that term gets raised to the power 1 and divided by 1. so the result is x.
-2x has the power 1 so that term gets raised to the power 2 and divided by 2. -2x^2/2 = -x^2
2007-12-03 19:05:28 · answer #3 · answered by adidas55dude 2 · 1⤊ 1⤋
If you're looking for an antiderivative then everyone is correct with x - x^2. However if you're looking for the indefinite integral you must have some constant. So the answer would be x - x^2 + C.
2007-12-03 19:08:15 · answer #4 · answered by none 2 · 0⤊ 1⤋
x - x^2
2007-12-03 19:03:50 · answer #5 · answered by LSEaves 2 · 0⤊ 1⤋
x - 2(x^2)/2 + c
= x - x^2 + c where c is a constant
2007-12-03 19:07:19 · answer #6 · answered by Kemmy 6 · 0⤊ 1⤋
The answer is: x-x^2.
2007-12-03 19:06:23 · answer #7 · answered by Ame 2 · 0⤊ 1⤋