English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

A long wire carrying a current of 1A runs along the x-axis & takes a circular detour in the x-y plane of a radius 5 cm. Whats is the magnitude & direction of the resultant magnetic field at a distance of 5 cm above the center of the circle?? someone please help...thanks in advance :)

2007-12-03 10:27:40 · 2 answers · asked by a.n. 1 in Science & Mathematics Physics

2 answers

Hmm, sounds like an od one. My guess is that you should add the magnetic field at the boundary with that from the straight section. So the field fromt the straight section is just (u I ) /(2 pi s) and the field from the loop part at the boundary is (u I). Where u is permiability of free space, I is current, s is distance to part that has to be measured..in this case s is 10cm. If your teacher didn't cover boundary condition equations then, my answer is probably wrong. But if he/she did...you should read up on this and try and see if my answer is correct. So the magnitude of the final answer should be u (1 + 1/(.2 Pi) ) hope that helps. Oh and the direction is out of the page. Which you can find by using the right hand rule for both parts

2007-12-04 05:35:22 · answer #1 · answered by Brian 6 · 0 0

the right suggestions-set is that made by the (worry-loose to the airplane of the table) to the sector intensity B. this suggestions-set is ninety-sixty 9 =21°. The flux is the dot synthetic from the discipline vector (known to the airplane of the table and pointing UP) and the ingredient of the Magnetic section intensity Vector (vertically pointing down). So the sign would be undesirable. Flux = -5.6*(10^-5)*(cos 21°)*(a million.a million*0.fifty 8) = wish this facilitates

2016-11-13 10:22:53 · answer #2 · answered by ? 4 · 0 0

fedest.com, questions and answers