physics question?

Question

Ice at 0.0°C is mixed with 6 × 10^2 mL of water at 23°C. How much ice must melt to lower the water temperature to 0.0°C?

Answer 1

Latent heat of fusion will be responsible for cooling the water
Q(ice)=Q(water)
m1Cf=m2Cp(T2-T1)
m1- mass of ice
m2- mass of water
Cf - coefficient of latent heat of fusion (334 J/g)
Cp - coefficient of specific heat of water(4.1813 J/(g K)
T2- T1 difference in temperature

m1= m2[Cp/Cf](T2-T1)
m2= (6 E+2 mL 1 g/mlL)
m2= 600 g

m1= 600[4.1813 /(334](23)
m1=173 g