Solve √4x-3+2=7?

Question

and SOLVE 6x^2-12x=0

THanks a million for your time and help!

Answer 1

Not sure how much of the equation is under the sqrt.
If it is sqrt(4x-3)+2=7

sqrt(4x-3)=7-2
sqrt(4x-3) = 5
4x-3=25
4x=28
x=7


6x^2-12x=0, factor out the 6 on the left
6(x^2-2x)=0, divide both sides by 6
x^2-2x=0, add 2x to both sides
x^2=2x, divide by x
x=2

Answer 2

sqrt of 4x-3+2=7

2x-1=7
2x=8
x=4

6x^2-12x=0
6x(x-2)=0
6x=0
x-2=0
x=0,2

Answer 3

sqrt 4 = 2 so 2x - 3 +2 = 7
2x = 8
x = 4


0 duh...