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How do you also find on the calculator? Thanks.

2007-12-03 07:39:04 · 5 answers · asked by ilovesoccer 1 in Science & Mathematics Mathematics

5 answers

OK

C = .01x^2 -90x +15000

Take first derivitive, and where this = 0 is max/min point

0=.02x -90
90 = .02x

4500 = x

At x = 4500

C = .01(4500)^2 - 90(4500) + 15000
C = 202,500 - 405,000 + 15,000
C = -187,500

Hope that helps.

2007-12-03 07:46:59 · answer #1 · answered by pyz01 7 · 0 0

This is a concave curve opening upward, this to find the minimum, we need to know when the derivative = 0 (that is, when a line tangent to the curve is parallel to the x-axis, which would represent the minimum value of the curve).

C' = 0.02x - 90
0.02x - 90 = 0
0.02x = 90
x = 90/0.02
x = 4500 units

Hope this helps! :)

2007-12-03 07:47:33 · answer #2 · answered by disposable_hero_too 6 · 0 0

well, considering that this equation is parabolic,......
the parabola opens up, and the vertical translation is up 15000 and it opens up from there, so the minimum cost of C must be the minimum value, which is 15000.
on the calculator, you would set x equal to 0 which still ends up being 15000

2007-12-03 07:45:55 · answer #3 · answered by Anonymous · 0 0

on a calculator, sketch the curve and trace along the graph till you reach the minimum point.

to do this analytically, take the derivative and set it equal to zero.

2007-12-03 07:43:38 · answer #4 · answered by Michael M 7 · 0 0

Assume C=0, and solve for x. You get three value for x, ignore the negatives, radicals and imaginary. .......

2016-05-28 00:41:13 · answer #5 · answered by ? 3 · 0 0

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