OK
C = .01x^2 -90x +15000
Take first derivitive, and where this = 0 is max/min point
0=.02x -90
90 = .02x
4500 = x
At x = 4500
C = .01(4500)^2 - 90(4500) + 15000
C = 202,500 - 405,000 + 15,000
C = -187,500
Hope that helps.
2007-12-03 07:46:59
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answer #1
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answered by pyz01 7
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This is a concave curve opening upward, this to find the minimum, we need to know when the derivative = 0 (that is, when a line tangent to the curve is parallel to the x-axis, which would represent the minimum value of the curve).
C' = 0.02x - 90
0.02x - 90 = 0
0.02x = 90
x = 90/0.02
x = 4500 units
Hope this helps! :)
2007-12-03 07:47:33
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answer #2
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answered by disposable_hero_too 6
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well, considering that this equation is parabolic,......
the parabola opens up, and the vertical translation is up 15000 and it opens up from there, so the minimum cost of C must be the minimum value, which is 15000.
on the calculator, you would set x equal to 0 which still ends up being 15000
2007-12-03 07:45:55
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answer #3
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answered by Anonymous
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on a calculator, sketch the curve and trace along the graph till you reach the minimum point.
to do this analytically, take the derivative and set it equal to zero.
2007-12-03 07:43:38
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answer #4
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answered by Michael M 7
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Assume C=0, and solve for x. You get three value for x, ignore the negatives, radicals and imaginary. .......
2016-05-28 00:41:13
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answer #5
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answered by ? 3
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