2005 x 2003-2004^2=-1 PROOF???

Question

2005 x 2003-2004^2=-1 PROOF???

Answer 1

Let n be a number:

Square it and subtract 1:
n² - 1

Difference of squares rule says:
(n + 1)(n - 1) = n² - 1

This can be rearranged to:
(n + 1)(n - 1) - n² = -1

Now just substitute in n = 2004 and you have your answer:
2005 x 2003 - 2004² = -1

Answer 2

2004^2=2004^2-1+1
=2005*2003+1

2005*2003-2004^2=-1 QED.

Answer 3

If you just do the arithmetic, you should get
2005 x 2003 = 4,016,015
2004^2 = 4,016,016
4,016,015 - 4,016,016 = -1

I supposed you could call this a "proof", but that's not usually the word used when you're just doing arithmetic.

Answer 4

4016015-4016016 = -1

do you not have a calculator?

you do multiplication on both sides and then subtract remember BEDMAS. brackets,exponets,divide,multiply,add,subtract.