The capacity of an elevator is either 15 children or 11 adults. If 11 children are currently in the elevator how many adults can still get in? What formula would I use to get this answer? Children=11/15adults?
2007-12-03 07:01:14 · 3 answers · asked by Jeremy B 2 in Science & Mathematics ➔ Mathematics
let the answer be x adults=15/11 children
then 11+x*15/11=15.
15x/11=4
x=4*11/15=44/15<3
onlt two adults can enter.
.
2007-12-03 07:09:02 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Assume that 15 children has the same mass as 11 adults.
15 c = 11 a
c = 11/15 a (as you stated)
11 children = (11) (11/15) adults
there is therefore the equivalent of 121/15 adults (8.0666) on the elevator
Therefore, 6 more adults can get on.
---- Edit.-----
Last line is wrong. I used 15 instead of 11 as the total number of adults.
CORRECT -
11 - 8.066 = 2.9333...
2 more adults can get on.
2007-12-03 07:07:25 · answer #2 · answered by Anonymous · 1⤊ 1⤋
truthfully the respond is 10 via fact each and every 6 adults are equivalent to ten babies , so if there is 6 adults under the skill, then 10 babies can share the elevator so the respond is 10
2016-12-17 05:54:44 · answer #3 · answered by ? 4 · 0⤊ 0⤋