Without graphing determine whether the line eith equation 3x+4y=5 is rising or falling and why?

Answer 1

Solve for y to get it in slope-intercept form:

3x + 4y = 5

Subtract 3x from both sides:
4y = -3x + 5

Divide both sides by 4:
y = (-3/4)x + (5/4)

From y = mx + b form, we know that the slope is -3/4 (and y-intercept is 5/4).

Because the slope is negative, it is falling.

Answer 2

ok
rearrange 3x + 4y = 5 into y=mx+c form, where m = gradient of line:
4y=5-3x
y= -3/4x + 5/4
in this equation, the coefficient of x (the number before it) tells you the nature of the line: if it is positive, then it is rising and going towards the top-right of the graph as with y=x, and if it is negative then it is falling. the "+5/4" simply tells you where it cuts the y axis

hope this is helpful!

Answer 3

3x + 4y = 5

arrange in slope intercept form y = mx + b

4y = -3x + 5

divide by 4

y = -(3/4)x + (5/4)

slope m = -3/4

When slope of a line is negative, the line falls as x increases

Answer 4

3x + 4y = 5
Put it in std. form (y = mx + b)
4y = -3x + 5
y = -3/4 x + 5/4

Note that the m term (slope) is -ve, so the line is falling.

Answer 5

what you want to do is first put this equation into y=mx+b form, so:

3x+4y=5
4y=-3x+5
y=-3/4x+5/4

m is the slope, so since the slope is negative (-3/4) it is falling.