Find the SLOPE of the line perpendicular to the line y=3x-2.?

Question

Rationalize the denominator 2/√7

THANK YOU! THANK YOU! THANK YOU!
FOR HELPING ME!

Answer 1

PROBLEM 1:

Your equation is in slope-intercept from (y = mx + b), so you know the slope of the first line is 3.

The slope of a perpendicular line is the "negative reciprocal". So take the reciprocal (1/3) and negate it (-1/3).

The slope of the perpendicular line is -1/3

PROBLEM 2:

Rationalize denominator of 2/√7

Multiply the top and bottom by √7:

2 x √7
-----------
√7 x √7

The denominator becomes 7:
2√7
------
.. 7

Answer 2

The slope of a perpendicular line to the line you have will always be opposite inverse. So the equation of the perpendicular line will be y = -1/3x. It might help if you think of 3 as being 3/1, so all you have to do is flip it and add a negative sign.

To rationalize the denominator, you need to get rid of the radical sign. To do this multiply by one, which in this case will be √7/√7. So the answer will be (2√7)/7. The denominator is just 7 because a square root squared cancels the itself out.

Answer 3

two lines are perpendicular if the product of their slopes is -1.

the line given has slope 3. to find the slope of the other line, just solve:

3m = -1
m = -1/3

to rationalize the denominator means to get rid of all radicals from the denominator. since it's simply a square root, squaring the denominator will get rid of the radical, so:

2/sqrt(7) = 2*sqrt(7)/sqrt(7)*sqrt(7) = 2*sqrt(7) / 7

or if you prefer,

2/7 * sqrt(7)

Answer 4

1. y=3x-2
its slope=3
desriedlope of the line perpendicular to it=-1/3 ANS.
2.2/sqrt(7)/sqrt(7)*sqrt(7)].
=2sqrt(7)/7. ANS.
=