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2007-12-03 06:29:09 · 2 answers · asked by puma820 2 in Science & Mathematics Mathematics

2 answers

I think the question is incomplete

did you mean: log base a 7 =6 therefore find log base a^2(7)???

if it is the same as you said then what "steiner1745" said is right.

2007-12-03 06:57:02 · answer #1 · answered by Appu 2 · 0 0

This equation is impossible.
Let x = log_a 7 = 6 log _a² 7.
Let's go to work on the last term.
6 log_a² 7 = log_a² 7^6 = x.
So a^(2x) = 7^6.
a^x = 7³.
But x = log_a 7
So a^x = 7.
Thus 7 = 7^3, which is impossible.

2007-12-03 14:48:56 · answer #2 · answered by steiner1745 7 · 0 0

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