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Find the area of the region enclosed by the lines y=x, x=3/4*Pi, and y=sin(x)?

2007-12-03 06:23:20 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

2 answers

A + B = C ?

2007-12-03 06:47:12 · answer #1 · answered by Anonymous · 0⤊ 0⤋

A =
3π/4
∫ [x - sin(x)]dx =
0
3π/4 + cos(3π/4) - 0 - cos(0)
A ≈ 0.6490877

2007-12-03 06:37:00 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋

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