solve squareroot 3x+6=21?

Answer 1

1.square both sides (Square root of 3x+2)^2= (21)^2 this gets rid of the square root on the left side of the equation.

2. You now have 3X+6=441

3. Now sub 6 from both sides 3X=435

4. Now divide by three on both sides and answer is X= 145

Answer 2

CASE 1: If you mean whole square root 3x
squareroot 3x=15
:. 3x=225 (squaring both sides)
:. x=75

CASE 2: If you mean square root 3 multiplied by x
squareroot 3x=15
:. x= 15/squareroot 3
= (15/squareroot 3) * (squareroot 3/squareroot 3)
Since (squareroot 3/squareroot 3) = 1
=15 * squareroot 3 / 3 [root 3 into root 3 is 3]
= 5* squareroot 3
or 5 * 1.732
= 8.66

Answer 3

Depends on whether it is:
√(3x + 6) = 21

Or:
√(3x) + 6 = 21

CASE 1:

Square both sides:
3x + 6 = 21²
3x + 6 = 441
3x = 441 - 6
3x = 435
x = 145

CASE 2:

√(3x) + 6 = 21

Subtract 6 from both sides:
√(3x) = 15

Square both sides:
3x = 15²
3x = 225
x = 75

Answer 4

I'm guessing you mean:
.._____
√(3x+6) = 21 ?

If so, square both sides first to get:

3x + 6 = 441

Then, subtract 6 from both sides to get:

3x = 435

Then, divide both sides by 3 to get:

x = 145

Answer 5

sqrt x + 6 = 21
sqrt x = 21 – 6 = 15
squaring both sides
3 x = 15^2 = 225
x = 75

Answer 6

i) For all x element of R, the two x² and (x - 5)? are ? 0; consequently the only element consists of a decision the inequality ideal it incredibly is the denominator, (x - 2)³ or on an analogous time as numerator = 0 ii) This function isn't defined for denominator = 0; ==> x = 2 And for all x < 2, (x - 2)³ < 0 iii) consequently from the above for x in (-?, 2), the given function is ? 0 and numerator is 0 at x = 0 ( contained in (-?, 2)) and at x = 5 so answer set = (-?, 2) and 5

Answer 7

3x+6=21
3x=21-6
3x=15
x=5
sq rt 5=2.236