Definte Integral?

Question

What is the definte integral of:

3xdx over the inberval [5,0]

Answer 1

I = integral(3x dx) = 3/2x^2 + c

Evaluate ot end points

I = 3/2*(5^2 -0) = 75/2

Answer 2

hehehe thats an extremely nasty one. enable u = sin(x) du/dx = cos(x) so du=cos(x)dx cos(x)dx is interior the begining so u can replace it to du, hence replace necessary to a minimum of one regarding u, and you get e^u, which integrates to e^u, so the required is e^sin(x) then sub x=0 and x=pi/4 so e^(a million/sqrt2)-e is ur answer wish that helps