Solve the system of equations by the addition method.?

Question

{3x - 5y = 5
{2x - 5y = 5

a. (0, -1)
b. (-1, 0)
c. infinite number of solutions
d. no solution

Answer 1

Okay, in order to make something (5y) cross out, multiply the top by -1.

We get:

-3x+5y=-5
Now keep
2x-5y=5

And combine these to get

-1x=0
x=0

Now plug 0 into either equation to get y.

3(0)-5y=5
-5y=5
y=-1

So the answer is:

a. (0,-1)

Answer 2

it's also called : "2 Equations , 2 Unknowns :"

>>>>>>>>>>>>>>>>>>>>3x - 5y = 5
multiply 2ND eq by -1>>>- 2x + 5y = - 5 now add 2 eq.
x= 0>>>> substitute it in any of the 2 original eq
y= -1
Answer then is a

Best Regards,

Answer 3

3x-5y=5
2x-5y=5(subtract equation two from equation one )
x-0=0
x=0
3(0)-5y=5
-5y=5
y=-1

Answer 4

3x - 5y = 5
- 2x + 5y = - 5-----ADD

x = 0

-5y = 5
y = - 1

x = 0 , y = - 1
OPTION a