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5x-4y=8
6x-y=21
Exactly by analytical means

2007-12-02 23:11:25 · 7 answers · asked by Anonymous in Science & Mathematics Mathematics

7 answers

5x - 4y = 8
-24x + 4y = - 84-----ADD
- 19x = - 76
x = 4

24 - y = 21
y = 3

x = 4 , y = 3

2007-12-02 23:28:33 · answer #1 · answered by Como 7 · 1 2

I would use substitution to solve this. Though elimination method would work well also.

Solve the second equation for y:

y = 6x - 21

substitute for the y in the first equation:

5x - 4(6x - 21) = 8
5x - 24x + 84 = 8
-19x = - 76
x = 4
y = 3

2007-12-03 07:21:58 · answer #2 · answered by Marley K 7 · 1 0

Multiply the second equation by -4:

-24x + 4y = -84........(3)

Now add equation (1) and (3)

-19x = -76
x = 4

Substitute y with 4 in any equation (I will choose 1)
5 * 4 - 4y = 8
20 - 4y = 8
-4y = -12

y = 3

x = 4
y = 3

2007-12-03 07:22:27 · answer #3 · answered by Anonymous · 0 0

5x-4y=8
6x-y=21

multiply each equation by 6 and then deduct i from ii.... You;ll get the value of y. Then place y value in either of the equations, you'll get value of x.

2007-12-03 07:22:22 · answer #4 · answered by ihrobin 5 · 0 0

Values of y:
5x - 4y = 8
4y = 5x - 8
y = (5x - 8)/4

6x - y = 21
y = 6x - 21

Value of x:
(5x - 8)/4 = 6x - 21
5x - 8 = 24x - 84
19x = 84 - 8
19x = 76
x = 4

Value of y:
y = (5(4) - 8)/4
y = (20 - 8)/4
y = 12/4
= 3

Answer: x = 4, y = 3

Proof:
6(4) - 3 = 21
24 - 3 = 21

2007-12-03 07:21:25 · answer #5 · answered by Jun Agruda 7 · 4 1

5x-4y=8
x=8,y=8

6x-y=21
x=4, y=3

2007-12-03 07:24:58 · answer #6 · answered by lm 4 · 0 1

5x-4y=8
24x-4y=84
19x=76
x=4
By the way which grade are you?

2007-12-03 07:21:27 · answer #7 · answered by ramesh_1960 3 · 1 1

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