Physics Problems?

Question

I have answers so I would really like help with the actual work to figure it out! Thanks!

A small crack occurs at the base of a 15.0 m high dam. The effective crack area through which water leaves is 1.30 x 10^-3 m^2. Ignoring viscous losses, what is the speed of water flowing through the crack? (Chapter 10)
a. 14.0 m/s

Answer 1

If you are ignoring viscous forces, the area of the hole should make no difference.

The only thing that counts is the "head" the pressure due to the depth of water at the hole.

http://en.wikipedia.org/wiki/Hydraulic_head

The equation becomes:
v = sqrt (2gh)
where g is the acceleration due to gravity (about 9.8 m/s^2) and h is the height of the water above the hole.

If you need the amount of water flowing out, then the area is enters into the equation.