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squares from each corner and folding up the sides. If the volume of the tray is to be 160 cubic inches and x is to be an integer,what size squares should be cut from each corner?

2007-12-02 14:10:26 · 3 answers · asked by veggiesubextrapickels 1 in Science & Mathematics Mathematics

3 answers

Imagine the squares cut from the corners have a side length of x.

After cutting and folding squares from each corner of side x, you will have length 14 - 2x, width 12 - 2x, and height x.

(14 - 2x) (12 - 2x) (x) = 160 cubic inches

4x^3 - 52x^2 + 168x = 160

This cubic equation has three roots, but only one interger answer, which is 2.

Verification:

(14 - 2x2) (12 - 2x2) (2) = ?

(14 - 4) (12 - 4) (2) = ?

10 x 8 x 2 = 160

2007-12-02 14:21:59 · answer #1 · answered by theopratr 3 · 0 0

x(14 -- 2x)(12 -- 2x) = 160
=> x(x -- 7)(x -- 6) = 40
=> x^3 -- 13x^2 + 42x -- 40 = 0
=> (x -- 2)(x^2 -- 11x + 20) = 0
giving x = 2 so 2 inch squares from the corners are to be cut.

2007-12-02 14:24:10 · answer #2 · answered by sv 7 · 0 0

x(12 - 2x)(14 - 2x) = 160
- 2x(x - 6)(14 - 2x) = 160
4x(x - 6)(x - 7) = 160
4x(x^2 - 13x + 42) = 160
x^3 - 13x^2 + 42x - 40 = 0
x = 2 in.

8 - 52 + 84 - 40 = 0

2007-12-02 14:58:22 · answer #3 · answered by Helmut 7 · 0 0

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