One number is 3 times another number. The sum of the smaller number and twice the larger number is 77. Write a system of equations that you could use to find the smaller number.
2007-12-02 13:39:20 · 7 answers · asked by Bad N 1 in Science & Mathematics ➔ Mathematics
Let S be the smaller number and L the larger.
"One number is 3 times another number."
L = 3 S
"The sum of the smaller number and twice the larger number is 77."
S + 2 L = 77
Two equations, two unknowns. To solve, use the first equation as a substitution for L in the second...
S + 2 ( 3 S ) = 77
7 S = 77
S = 11 so L must be 33.
2007-12-02 13:42:40 · answer #1 · answered by jgoulden 7 · 0⤊ 0⤋
use x as the larger number and y as the smaller number.
Therefore, x=3y from the first statement.
For the second: y+2x=77
{x=3y
{y+2x=77
Change the first equation into 3y-x=0 by moving things around.
Multiply the second by -3 to get -3y-6x=-231
Add the two equations.
You get x=33, so y=11
2007-12-02 13:46:21 · answer #2 · answered by nicknameyo 3 · 0⤊ 0⤋
x + 2(3x) = 77
=> 7x = 77
=> x = 11 other number = 3x = 3*11 = 33
2007-12-02 13:44:49 · answer #3 · answered by sv 7 · 0⤊ 0⤋
Sometimes good people out number bad people but it is also correct that sometimes bad people out number good people. Nowadays politicians in most of the countries are corrupt and are in majority.
2016-05-27 08:04:06 · answer #4 · answered by Anonymous · 0⤊ 0⤋
suppose the smaller no is x and the larger no is y
y=3x
x+ 2y = 77
sub the y=3x into the second eqn
x+ 6x = 77
7x=77
x=11
therefore the smaller no is 11!!!!!!!!
2007-12-02 13:48:01 · answer #5 · answered by lazylady_stel 2 · 0⤊ 0⤋
77 = x + 2h
77/2h = x
x = 77/2h
2007-12-02 13:44:36 · answer #6 · answered by Anonymous 3 · 0⤊ 0⤋
x = 3y --> x -3y = 0 --> 2x -6y = 0
y + 2x = 77
Subtract one equation from the other, and eliminate x.
7y = 77
y = 11
x = 33
2007-12-02 13:44:51 · answer #7 · answered by Edgar Greenberg 5 · 0⤊ 0⤋