A Coconut falls from the top of a tree and raches a velocity of 19.6 m/s when it hits the ground. It takes 2 seconds to reach the ground. What is the coconuts acceleration?
[[ Please help me with this. I do not understand it. Please show step by step how to get the answer, and what to write. Thank You ]]
2007-12-02 13:21:46 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Physics
19.6 m/s / 2 seconds = 9.8 m/s²
2007-12-02 13:30:06 · answer #1 · answered by Tim C 7 · 1⤊ 0⤋
That's kind of a crazy question.
Acceleration (due to gravity) is 9.8 m/s^2.
That is a constant used for many physics equations.
Now, your problem specified the time and the velocity so they are a neat package. Usually the question is asked like this:
A coconut falls from the top of a tree and reaches a velocity of 19.6 m/s when it hits the ground. How lond did it take to reach the ground?
2007-12-02 13:28:56 · answer #2 · answered by The Tester 3 · 0⤊ 0⤋
The acceleration of the coconut is the same old well established 9.8 m/s/s. It is a constant on our planet ,the earth and same for any falling object, whether it is a coconut or a feather, uncle Galileo proved it. So you don't need afresh a coconut to determine it.
2007-12-02 13:36:47 · answer #3 · answered by Venkat R 6 · 0⤊ 0⤋
the formula is distance equals rate multiplied by time
so you have to write d=rt
the t is the number of seconds since the object was thrown/falling
so 2 seconds
the d is the distance in meters (how far it fell)
the r is the rate of velocity in meters per second 19.6
so as of now you should have written d= 19.6 * 2
do that
the next step is up to you
go here for some help
http://sg.answers.yahoo.com/question/index?qid=1006032305397&show=7
2007-12-02 13:42:59 · answer #4 · answered by full metal 2 · 0⤊ 0⤋
Acceleration = (final velocity - initial velocity)/ time
= (19.6-0)/2
=9.8ms^-2
Its just making use of the equation of acceleration.
Hope it helps.
2007-12-02 13:27:10 · answer #5 · answered by sy 1 · 0⤊ 0⤋
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2016-12-10 10:43:06 · answer #6 · answered by Anonymous · 0⤊ 0⤋
19.6/2=9.8 m/s^2. BAM!
2007-12-02 13:24:35 · answer #7 · answered by hyungbinkim 3 · 0⤊ 0⤋
v=sq root or 2gh, where g is gravity or acceleration, and h is height or distance
v = d*time like mph or m/s
v=d*t
19.6m/s=d*2s
d=19.6m/2d
d=9.8m or height in this case
v=sq rt of 2gh
solve for g so you sq both sides
vsq = 2gh
solve for g
vsq/2h=g
{19.6m/s*19.6m/s}/2*19.6m=g
19.6m/ssq/2= 9.8m/ssq
or 9.8 meters per second per second
2007-12-02 13:37:11 · answer #8 · answered by diver down below 2 · 1⤊ 0⤋