it started out as 1x3-4x (the 3 is an exponent)
and i know you can take x out of both of those so i did this
1x3/x - 4x/x
and then i got to re write whats left with the x on the outside of the parenthesis.
x(????)
thats as far as i got :P help please!
2007-12-02 12:35:03 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x^3-4x
x(x^2-4)
x(x-2)(x+2)
2007-12-02 12:38:51 · answer #1 · answered by Dave aka Spider Monkey 7 · 1⤊ 0⤋
1x^3-4x
= x ( x^2 - 4 )
= x ( x^2 - 2^2 )
Now use the formula A^2 - B^2 = ( A + B ) ( A - B )
=> x [ ( x + 2 ) ( x - 2 ) ]
=> x ( x - 2 ) ( x + 2 ) ............ Answer
2007-12-02 20:45:52 · answer #2 · answered by Pramod Kumar 7 · 0⤊ 0⤋
x(x-2)(x+2)
2007-12-02 20:50:07 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Answer: x (x+2)(x-2)
To check it out just multiply it.
2007-12-02 20:41:39 · answer #4 · answered by Manny Angel 2 · 0⤊ 0⤋