I neep help please?

Question

I need help with this math probem i cannot understand it:

Mia went downtown by bus, traveling at 60 km/h. She walked home at 6 km/h. Her total traveling time was 2.75 h. How far did she travel?

Nothin was missed btw, but my dad somehow got 15

Answer 1

Wow! Is that your photo? Of course there is enough information, but one can not just hope you add some numbers to get an answer. Mathematics is precise so we must be able to explain at each step the justification for it.

Call the distance one way x. From d=rt we can solve for time to get t = d/r.

So time by bus is x/60 and time walking is x/6 and these two times add up to 2.75 hours so we can write the equation

x/60 + x/6 = 2.75 and multiplying thrrough by 60 and solving for x gives

11x = 60(23.75) and dividing by 11 give x = 15 km.

So the round trip is 2 times 15 = 30 km

Answer 2

Here's the thing: She starts at home, goes downtown and comes home. The distance is the exact same both ways, right?

So what you need to do is find out how far you can go on a bus at 60 km/h before you have to stop and walk balk home at 6 km/h.

For example, if Mia spends one hour on the bus to get downtown, she is 60 miles from home, right? So tell me how long it will take for her to get home walking? Walking 6 km/h means it will take her 10 hours to get back!

60 km / 6 km/h = 10 hours. Add 10 hours walking to the 1 hour on the bus and you have 11 hours.

Oh boy, waaaayy too long, right? So what do we know from this example? That Mia has to spend MUCH less time on the bus. Let's try another example:

Mia spends 15 minutes (0.25 hours) on the bus, which means she gets 15 km from home. (60 km/h means you travel 1 km per minute.) So now she needs to get home walking at 6 km/h. 15 km (the total distance she has to walk home) divided by 6 km/h (the speed she walks) equals 2.5 hours.

Add 2.5 hours walking to 0.25 on the bus and you have 2.75 hours! That means she went exactly 15 km downtown and 15 km back, for a total of 30 km!!

Answer 3

The distance she walked has to be the same distance coming back, so:

60x = 6y

where x is the time traveled at 60 and y is the time traveled at 6.

Then, the total time is the sum of both travel times:

x + y = 2.75

Now just solve by substitution. Enjoy.


EDIT:

Apparently, there are some algebraic non-believers answering...

She drove for 15 minutes and walked for 2 1/2 hours. The distance was 15 km.

Answer 4

distance (in Miles) = 2.75*60*6/(60 + 6) = 15 miles.
This is from going time + returning time = total time
distance/60 + distance/6 = 2.75
or distance(1/60 + 1/6) = 2.75
or distance(60 + 6)/60*6 = 2.75
or distance = 2.75*60*6/(60 + 6)

Answer 5

60x + 6y = 2.75 solve for x and y. x is the distance she traveled on the bus, and y is the distance she traveled walking... but I dont know how you would do this without a quadratic equation so maybe you missed something in the problem

Answer 6

Let D represent distance travelled each way.
Time spent is distance over speed.
So D/60 + D/6 = 2.75 hours.
11D/60 = 2.75
11D = 60(2.75)
D = 60(2.75)/11
D = 15
total 30km

Answer 7

i think you add the 60+6 and that gets 66 then divide that by 2.75 and you get 24km

Answer 8

the thing that makes this problem work is you assume Mia goes the same distance inbound and outbound. try that approach.

Answer 9

Not enough info to answer the question. You need to at least know the time she done each speed.

Answer 10

i hate these kinda problems cause whose actually gonna get home and calculate the speed their walkin and be like wow i jus walked so and so miles :D