Determine the derivative of x^2 -xy +y^2 =7.
I did 2x - [ydy/dx + x] + 2ydydx = 0 and I know thats where I made the mistake.
So basically, can someone show me what I'm doing wrong? Thanks :)
2007-12-02 12:07:02 · 5 answers · asked by Maike Tater 2 in Science & Mathematics ➔ Mathematics
Derivative is:
2x -y -xdy/dx +2ydy/dx = 0
2x - y + (2y-x)dy/dx = 0
dy/dx = (y-2x)/(2y-x)
2007-12-02 12:12:39 · answer #1 · answered by nyphdinmd 7 · 0⤊ 0⤋
the right answer is
2x - [ x (dy/dx) + y ] + 2y (dy/dx) = 0
you should differentiate y when leaving x along
differentiate x when leaving y along
2007-12-02 12:14:06 · answer #2 · answered by KingTo H 2 · 0⤊ 0⤋
You didn't differentiate the product -xy correctly.
The derivative of -xy is
-[ x(dy/dx) + y(dx/dx)] which simplifies to
-x (dy/dx) - y
The rest looks ok.
2007-12-02 12:10:56 · answer #3 · answered by answerING 6 · 0⤊ 0⤋
maybe they wanted you to solve it for d/dy? i dont see anyhting wrong
2007-12-02 12:11:52 · answer #4 · answered by notzimmer 2 · 0⤊ 0⤋
i tried checking it but it looks correct
2007-12-02 12:10:50 · answer #5 · answered by Anonymous · 0⤊ 0⤋