English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

Stephanie and Kaylee can finish apiece of work in 5 11/30 days. Stephanie can do the job herself in seven days. If Kaylee wanted to do the job alone, how long would it take her?
Answer :23 days

2007-12-02 12:06:20 · 5 answers · asked by janie 2 in Science & Mathematics Mathematics

is this an example of a radical function?

2007-12-02 13:25:20 · update #1

5 answers

[11]
They can do the work in 5 11/30 or 161/30 days
Therefore in 1 day,they can do 30/161 part of the work
Stephanie can do the job herself in 7 days
Therefore in 1 day she can do 1/7 part of the job
So,working alone Kaylee can do (30/161 -1/7) or 7/161 part of the job in 1 day
Therefore Kaylee can do the job working herself in 161/7 or 23 days

2007-12-02 12:14:10 · answer #1 · answered by alpha 7 · 0 0

It takes them 5 11/30 = 161 / 30 days to do the job together, so working together they can do 30 / 161 of the job per day.

Stephanie does 1/7 of the job per day working alone. What does that leave for Kaylee?

30 / 161 - 1 / 7
30 / 161 - 23 / 161
7 / 161

Therefore Kaylee does a mere 7 / 161 part of the job in 1 day and it will take her 161 / 7 = 23 days to do the job alone.

2007-12-02 12:12:33 · answer #2 · answered by jgoulden 7 · 0 0

Let t = time it takes Kaylee to do the job alone
1/t = amount of job Kaylee can do in one hour (rate per hour)
1/7 = amount of job Stephanie can do in one hour

5 11/30 = 161/30 = time together

rate x time = amount of work

(1/t )(161/30) + (1/7)(161/30) = 1

161/(30t) + 23/30 = 1
161/(30t) = 7/30
161/t = 7
t = 161/7 = 23
There's your 23 days. hope this is clear!

2007-12-02 12:14:11 · answer #3 · answered by Marley K 7 · 0 0

what do you mean by 511/30?

try an equation and assigning numbers to variables

2007-12-02 12:12:47 · answer #4 · answered by Anonymous · 0 0

jgoulden is correct.

2007-12-02 12:13:49 · answer #5 · answered by Anonymous · 0 0

fedest.com, questions and answers