A horiztonal force of 10 N is applied to a 1.0 kg block sitting on a flat surface. The coefficient of static friction between the block and the surface is 0.80, and the coefficient of kinetic friction is 0.70. Plot the velocity of the block as a function of time over the first five seconds. My question: how do you find the plot points?
2007-12-02 11:38:03 · 1 answers · asked by mathfan09 1 in Science & Mathematics ➔ Physics
First, determine if 10N is sufficient to overcome static friction:
1*9.81*0.80
7.848<10, yup
The force of friction while moving is
1*9.81*0.70
6.867 N
So the net force is
10-6.867
3.133 N
using F=m*a, find a
3.133=1*a
a=3.133 m/s^2
v(t)=3.133*t
plot that function for 0<=t<=5
It's a straight line starting at zero
with slope 3.133
BTW: position
s(t)=.5*3.133*t^2
j
2007-12-03 06:11:10 · answer #1 · answered by odu83 7 · 0⤊ 0⤋