A rod made from a particular alloy is heated from 24.5°C to the boiling point of water?

Question

Its length increases by 8.35 x 10^-4 m. The rod is then cooled from 24.5°C to the freezing point of water. By how much does the rod shrink?


(please give whole problem workout) thanks in advance

Answer 1

We know that the change in length dL is a product of coefficient of thermal expansion u times length L and change in temperature (T2-T1)
dL=uL(T2-T1)
so
u = dL/L(T2-T1)

and also
dL2= uL(T1-T3)

dL2=[dL/L(T2-T1)]L(T1-T3)

finally
dL2=dL(T1-T3)/(T2-T1)
dL2= 8.35 E - 4 (24.5 - 0)/(100 - 24.5)
dL2=2.71 E - 4 m

Answer 2

we would need to know the length of the rod at it's initial temperature.
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