Factor completely
6. 64 + a^3
7. 2x^4 + 16x
8. 32a^4 - 162b^4
2007-12-02 11:01:12 · 4 answers · asked by magicalskittlz 2 in Science & Mathematics ➔ Mathematics
6. (4+a)(a^2 - 4a + 16)
7. 2x(x^3 + 8)
2x(x^2-2x+4)(x+2)
8. 2(2a+3b)(2a-3b)(4a^2 +9b^2)
2007-12-02 11:13:07 · answer #1 · answered by Anonymous · 1⤊ 0⤋
64 + a³ = (4+a)(16 - 4a + a²)
2x^4 + 16x =
2x(x³ + 8) =
2x(x + 2)(x² - 2x + 4)
32a^4 - 162b^4 =
2(16a^4 - 81b^4) =
2(4a² + 9b²)(4a² - 4b²) =
2(4a² + 9b²)(2a + 3b)(2a - 3b)
2007-12-02 11:15:08 · answer #2 · answered by Philo 7 · 1⤊ 0⤋
6. 64 + a^3 = 4^3+a^3= (4+a)(16-4a+a^2)
7. 2x^4 + 16x =x^4 +8x= x(x^3+8)=x(x^3+2^3)= x(x+2)(x^2-2x+4)
8. 32a^4 - 162b^4= 2(16a^4-81b^4)=2(4a^2-9b^2)(4a^2+9b^2)
2007-12-02 11:09:49 · answer #3 · answered by coucou_bambie 2 · 1⤊ 1⤋
8. 2(2t - 3z)(2t + 3z)(4t^2 + 9z^2)
7. 2x (x + 2)( x^2 - 2x +4)
6. (x+4)(x^2 - 4x +16)
2007-12-02 11:08:26 · answer #4 · answered by Lottery 1 · 1⤊ 0⤋