Stoichiometry Question?

Question

Methanol, CH*3OH, is used in the production of many chemicals. Methanol is made by reacting carbon monoxide and hydrogen at high temperature and pressure.

CO(g) + 2H*2(g) --> CH*3OH(g)

a) How many moles of each reactant are needed to form 6.00 times 10*2g of CH*3OH?

b) Calculate the number of grams of each reactant needed to produce 10.0 mol of CH*3OH.

c) How many grams of hydrogen are necessary to react with 5.74 mol of CO?

Answer 1

CO => 28 g/mol.
H2 => 2 g/mol.
CH*3OH => 32 g/mol.
a)
(600 g CH*3OH) / (32 g/mol) = 18.75 mol
CO : 18.75 mol
H2 : 37.5 mol.
b)
10 mol CO = 280 g
20 mol H2 = 40 g
c)
2(5.74 mol.)(2 g/mol) = 22.96 g H2