Physics Question?

Question

An 18 kg box is released on a 37 degree incline and accelerates down the incline at 0.270 m/s^2. Find the friction force impeding its motion. How large is the coefficient of friction?

Please show and explain all work please.

Answer 1

First, solve for the net force parallel to the incline

F=18*0.270
F=4.86 N

now, F=m*g*sin(37)-f
where f is friction
f=101.4 N

f=m*g*cos(37)*µk
µk=0.719

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