I assume you are only looking for the centroid.
The centroid is located at the average of the coordinates.
x = (0 + 4 + 8)/3 = 12/3 = 4
y = (1 + 7 - 3)/3 = 5/3
The centroid is located at (x, y) = (4, 5/3).
2007-12-02 09:58:52
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answer #1
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answered by Northstar 7
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9
2007-12-02 17:51:07
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answer #2
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answered by Iceprincess 2
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alright ive spent a godd 10 mintues working on this and i finally have (5.375,1.75) for the centroid
to do this i first had to find the midpoints of each line segment using the (x1+x2)/2 , (y1+y2)/2 for each one and i got,,,
2,4
6,2
4,-1
the i found the perpendicular line going through each one, although as i found out after i finished you really only need two,
i did this using substitution of the x and y coordinates
(-2/3)X+5.333333
(2/5)X -.4
2X - 9
the graph at least two of them and find the intersection ( i used a TI-84)
im currently a sophomore in high school and we did this last year in geometry so i might not have gotten everything right, but im pretty sure. hope i could help =]
2007-12-02 18:09:54
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answer #3
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answered by Anonymous
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if you want the vertices of a triangle congruent to STU, there are an infinite number of solutions. one is (0,2), (4,8), and (8,-2)
2007-12-02 17:54:34
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answer #4
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answered by Person 4
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9 i think
2007-12-02 17:53:22
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answer #5
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answered by Anonymous
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Ouch.
I thought i was good at math...
*studies more*
2007-12-02 17:50:40
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answer #6
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answered by aleve909 3
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answering your question would prove me smart and not answering your stupid question would make me dumb.
2007-12-02 17:54:14
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answer #7
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answered by Nikhil007 2
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what is concurrency or cetroid?
2007-12-02 17:51:38
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answer #8
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answered by Anonymous
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no one is doing your mathhomewok girl.
2007-12-02 17:50:50
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answer #9
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answered by Anonymous
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4,3 i think i did it right
2007-12-02 17:56:52
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answer #10
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answered by Kristen S 3
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