equation of the line throughthe two points (3,1) and (9,5)?

Answer 1

First Find the Slope:
Step1: [Y(2) - Y(1)] / [X(2) - X(1)]
Step 2: (5-1) / (9-3)
Step 3: 4/6
Step 4: reduce the fraction and Slope= 2/3

Then use y=mx+b to find "b":
m is the slope; b is the y intercept; y=mx+b is the equation for a line
Step 1: substitute using one of the points (3,1)
1=(2/3)3+b
Step 2: solve for "b": 1=2+b
1-2=b
b=-1
Step 3: Plug your calculated m and b into th equation
Final Answer: y=(2/3)x-1

Kind of hard to do this on the computer.

Answer 2

First find the slope of the line:
Slope = (Yvalue2 - Yvalue1) divided by (Xvalue2 - Xvalue1)
= (5 -1) divided by (9-3) = 4 divided by 6 = 2/3.

Now you have the equation:
y = 2/3x + b

Plug in any point to find the value of B:

1 = (2/3)(3) + b
1 = 2 + b
b = -1

Therefore the equation of the line through these two points is
y = (2/3)x - 1

Answer 3

Slope of line = Y2-Y1 5 - 1 4 2
---------- = -------- = ----- = ---
X2-X1 9 - 3 6 3
y - 2 = (2/3)(x -1)

Just guessing on using the point slope for the equation!

Answer 4

slope = (5-1)/(9-3)=4/6=2/3

y = 2/3x + b

1 = 2/3(3) + b
b = -1

eq is y= 2/3x - 1