1 = 2x^2 + 4x - 6
2007-12-02 09:25:51 · 2 answers · asked by oc_xc 2 in Science & Mathematics ➔ Mathematics
wouldn't x = -2 and 3/2 if you factor it? and when you put those back in the equation you don't get one
2007-12-02 09:36:56 · update #1
quadractic worked, thanks!
2007-12-02 09:42:42 · update #2
In general, whenever you have an equation of the form
a x^2 + b x + c = 0
the values of x can be found from the quadratic equation
x = ( - b +/- sqrt ( b^2 - 4 a c ) ) / 2 a
where the +/- means that you get two answers, one from + and one from -.
You have
1 = 2 x^2 + 4x - 6.
Subtract 1 from each side to get
0 = 2 x^2 + 4x - 7
and use the quadratic equation above to find the two possible values of x.
2007-12-02 09:31:23 · answer #1 · answered by jgoulden 7 · 0⤊ 0⤋
1 = 2x^2 +4x -6
1 = (2x - 2) (x + 3)
X = 1, -3
2007-12-02 09:30:09 · answer #2 · answered by Rick 2 · 0⤊ 1⤋