2007-12-02 09:20:01 · 14 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
It's just an expression, not an equation, so it can't be solved. x can take any value.
2007-12-02 09:22:41 · answer #1 · answered by Charlie149 6 · 0⤊ 1⤋
you cannot solve the expression unless it is an eq like
x^2+8x+7 = 0
then you factorize it
(x+7)(x+1)=0
x+7 = 0, x = -7 or x+1=0, x=-1
2007-12-02 09:23:39 · answer #2 · answered by norman 7 · 0⤊ 0⤋
x= -1, x= -7
2007-12-02 09:25:34 · answer #3 · answered by karimus 1 · 0⤊ 0⤋
x=-7 or x=-1
2007-12-02 09:22:18 · answer #4 · answered by Evil spoon 2 · 0⤊ 1⤋
8x^3+7
2007-12-02 09:28:44 · answer #5 · answered by Anonymous · 0⤊ 0⤋
if you are solvign you need to find x
ifrst make it equal to zero
factor
x^2+8x+7=0
(x+7)(x+1) =0
now use the ZERO PROPERTY
(x+7) =0 or (x+1) =0
x=-7 or x=-1
2007-12-02 09:23:32 · answer #6 · answered by a c 7 · 0⤊ 0⤋
(x + 7)(x + 1)
x= -7, -1 if set = to 0
2007-12-02 09:25:17 · answer #7 · answered by Mr bubbles 2 · 0⤊ 0⤋
I evil spoon is right and here is how it is done
x^2+8x+7
(x+7)(x+1)
x=-7 or x=-1
you have to factor out the formula
2007-12-02 09:29:23 · answer #8 · answered by cekicgrad2006 1 · 0⤊ 0⤋
This is not an equation so there is nothing to solve. However, if you want the zeros, set this equal to zero, factor and solve for x:
(x + 1)(x + 7) = 0
x = -1, -7
2007-12-02 09:23:24 · answer #9 · answered by duffy 4 · 1⤊ 1⤋
this equation is not complete
for complete equation must write equal to
I assume your question is like this
x^2 + 8x+ 7 = 0
Now it is equation with second degree and one unknown
can be solved
(x+7)*(x+1)=0
x + 7 = 0
x = -7
x +1=0
x = -1
therefor x has two values they are
x = -7
x = -1
2007-12-04 16:08:17 · answer #10 · answered by Rayan Ghazi Ahmed 4 · 0⤊ 0⤋
This has no equation sign, therefore we cannot solve for an unknown. As you have seen this "expression" can be factored. Expression is the technical word.
2007-12-02 09:32:42 · answer #11 · answered by gzlakewood@sbcglobal.net 4 · 0⤊ 0⤋