Find the LCM for 3, 15, and 24.
2007-12-02 09:17:02 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Factors of 3 are 3, 1
Factors of 15 are 5, 3, 1
Factors of 24 are 8, 3, 1
Therefore, the LCM is 8 x 5 x 3 x 1
= 120
2007-12-02 09:21:38 · answer #1 · answered by duffy 4 · 0⤊ 0⤋
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RE:
Find the LCM for 3, 15, and 24.?
Find the LCM for 3, 15, and 24.
2015-08-10 19:52:21 · answer #2 · answered by Hamlet 1 · 0⤊ 0⤋
First write down the prime factors of each:
3 = 3
15 = 3 x 5
24 = 2 x 2 x 2 x 3
So the LCM must be 2 x 2 x 2 x 3 x 5 = 120.
2007-12-02 09:24:55 · answer #3 · answered by jgoulden 7 · 0⤊ 0⤋
Factor all three: 3 (3), 15 (3,5), 24 (2^3,3)
Thus we are dealing with 2's, 3's, and 5's. The lowest common multiple is the minimal set that covers all the factors for each. In this case, the minimal set contains three 2's, one 3, and one 5, or {2,2,2,3,5}. This set can cover the factor sets for the three given numbers {3}, {3,5}, and {2,2,2,3}.
2*2*2*3*5 = 8*15 = 4*30 = 120.
2007-12-02 09:25:30 · answer #4 · answered by Anonymous · 1⤊ 0⤋
3,15,24, all divided by 3
1,5,8, since no more commons, do 5*8=40
40*3=120, and that's the lcm
2007-12-02 09:25:31 · answer #5 · answered by Harris 6 · 0⤊ 0⤋
Lcm Of 3 And 15
2016-10-18 07:53:19 · answer #6 · answered by ? 4 · 0⤊ 0⤋
3x5x8 = 120
120/3 = 40
120/15=8
120/24=5
2007-12-02 09:21:37 · answer #7 · answered by norman 7 · 1⤊ 0⤋
1020
2007-12-02 09:20:15 · answer #8 · answered by Evil spoon 2 · 0⤊ 2⤋
120 it is. It's the lowest number that can be divided by all three.
2007-12-02 09:25:35 · answer #9 · answered by coastie mom 3 · 0⤊ 0⤋
there isnt
2007-12-02 09:22:27 · answer #10 · answered by teedotttt 2 · 0⤊ 1⤋