The length of a rectangle is 9 in. more than twice its width. If the perimeter of the rectangle is 36 in., find the width of the rectangle.
Your options are:
A) 2 in.
B) 3 in.
C) 4 in.
D) 5 in.
2007-12-02 09:08:47 · 5 answers · asked by Anonymous in Education & Reference ➔ Homework Help
L = 9 + 2W
2L + 2W = 36
So (18 + 4W) + 2W = 36
6W = 18
W = 3
B)
2007-12-02 09:18:52 · answer #1 · answered by Computer Guy 7 · 0⤊ 0⤋
Let the width of the rectangle be x. The length is 2x+9.
Perimeter = 2*(l+b) = 2*(x+2x+9)
6x + 18 = 36
6x = 18
So, x = 3
So, the width is 3
To confirm, you can calculate the perimeter as 2*(3*3 + 9) = 36.
2007-12-02 09:23:18 · answer #2 · answered by SM 2 · 0⤊ 0⤋
its B)3in
width-x
length-2x+9 (two times the width plus nine)
perimeter of a rectangle- 2length+2width
2x+2(2x+9)=36 write equation
2x+4x+18=36 distribute the 2
6x+18=36 combine like terms
6x=18 subtract 18 from both sides
x=3 divide by six
Note: last 2 steps are isolating the variable
hope it helps
2007-12-02 09:24:44 · answer #3 · answered by soccergeekster9 1 · 0⤊ 0⤋
First make your formulas:
(let L=length and W=width)
L=2W+9
L+L+W+W=36
Simplify:
2L+2W=36
Substitute L for 2W+9:
2(2W+9)+2W=36
Simplify:
(2W+9)+W=18
3W+9=18
3W=9
W=3
So the answer is B, 3 in.
2007-12-02 09:20:42 · answer #4 · answered by violingirl7777 3 · 0⤊ 0⤋
c. 4in
2007-12-02 09:17:10 · answer #5 · answered by ricky 2 · 0⤊ 1⤋