A cylinder can hold three tennis balls. if the volume of a tennis ball is 36pi, then what is the volume of can

Answer 1

Let radius of cylinder = r = radius of ball
(4/3)π r³ = 36 π
r³ = 27
r = 3
d = 6
h = 18
V (cylinder) = π r² h
V (cylinder) = π (9) (18) = 509 units³

Answer 2

Assuming that the tube is a cylinder and holds the balls tightly:

Volume of a ball:
V=4/3πr^3=36π.

Therefore r=((3/4)•36)^(1/3) = 27^(1/3)= 3.

Therefore the radius of the cylinder is 3, and the height of the cylinder is three times the diameter of each ball: h=3•2r=3•6=18.

This gives the volume of the cylinder is
V=πr^2h= π•3^2•18 = 162π.

Answer 3

The volume of the cylinder is 162 pi.

Here's why/how:

One ball's volume, 4 pi r^3 / 3 = 36 pi, so that r^3 = 27, i.e, r = 3.

The height h of the cylinder is 6 r (= 3 diameters of 2r each).

Its volume is therefore

pi r^2 h = pi 3^2 * 6*3 = 9*18 pi = 162 pi.

Live long and prosper.

Answer 4

From the volume of the sphere, determine its radius. Assuming the sphere fits snuggly, the cylinder has the same radius.

The cylinder can hold three tennis balls in a row. This means it is three tennis balls in height.

Use the cylinder volume formula with this radius and height.

Answer 5

if it holds three tenis balls, then its height is equal to 3 times the diameter and its radius equal to the radius of the tennis ball
u know that the volume of the tennis ball (sphere) = 36pi
so 4/3 * pi * r^3 = 36pi
so r = 3

the volume of a cylinder is
pi * r^2 * h, where h is just 3*d = 2*2*r = 12

so volume =
pi * 9 * 12 = 108pi

Answer 6

V=36Pi=r^3*4*Pi/3
r=3
Can diameter=6 and height = 18
Volume of can= A*h=Pi*3^2*18=162*Pi

Answer 7

The volume of a sphere is 4/3*π*r^3 which converts to (π*D^3)/6
Since a cylinder holds three stacked tennis balls:
36 = 3*(πD^3)/6
D=2.84
The height is 3*2.84=8.52
the base has an area of π*1.42^2 = 6.335
V = 8.52*6.335 =53.97pi

Answer 8

36(pi) = 4/3 (pi) r^3

(36pi)/(4/3 (pi) ) = r^3

~27 = r^3

r = 3 (approximately)

(18)(pi)3^2 = 508.93

v = 508.93 units^3