Physics Question?

Question

A 62.0 kg person jumps from rest off a 10.0 m high tower straight down into the water. Neglect air resistance during the descent. She comes to rest 3.00 m under the surface of the water. Determine the magnitude of the average force that the water exerts on the diver. This force is nonconservative.

Answer 1

First we need to know the speed just as she hits the water.

2 a h = v^2

2 ( 9.8 m/s^2 ) ( 10 m ) = v^2

Solve for the velocity v.

For the second part, we'll put the origin three meters under the water. Just as she hits the water her total energy is

1/2 m v^2 + m g h

1/2 ( 62.0 kg ) ( v^2 ) + ( 62.0 kg ) ( 9.8 m/s^2 ) ( 3.00 m )

When she comes to rest, her energy is zero. This change in energy must be the result of work done on her by the water. Work is force over distance, so

F ( 3.00 m ) = ΔE

Solve for F.

Answer 2

Physics question?

Yes, this is a physics question.