M is the line 2x-3y-12=0 that cuts the x-axis at p and the y axis at q.
1.find the co-ordinates of p and the co-ordinates of q.
2.find the area of the triangular region enclosed by M,the x-axis and the y axis.
ty in advance for your help.
2007-12-02 08:38:58 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
please explain how u did it.
2007-12-02 08:39:21 · update #1
3y = 2x - 12
y = (2/3)x - 4
Cuts x axis when: -
(2/3)x - 4 = 0
(2/3)x = 4
x = 6
Point (6 , 0)
Cuts y axis when:-
y = - 4
Point (0 , - 4)
Area = (1/2) (6) (4) units²
Area = 12 units²
2007-12-03 03:40:10 · answer #1 · answered by Como 7 · 1⤊ 1⤋
2x-3y-12=0 can be expressed as
y = (2x - 12)/3
Where M cuts the x-axis, the y-value will be zero. Where M cuts the y-axis, the x-value will be zero. So substitute y=0 in the equation above to get x, then substitute x=0 in the same equation to get y.
If x=0, then y = - 4. You should be able to work out what x is when y=0.
This will now let you draw the line M easily on a sheet of graph paper, since you know the co-ordinates of two points on it. You'll find it makes a right-angled triangle with the x- and y-axes. The area of a right-angled triange is half the area of a rectangle with the same sides as those including the right-angle. Now, you can easily read these two sides off the graph. This will give you the answer you want.
2007-12-02 08:54:18 · answer #2 · answered by kinning_park 5 · 1⤊ 0⤋
well... u change 2x -3y - 12 = 0
to y = 2/3x - 4
then u graph it and find x =6 y = -4
it makes a right triangle with hypotenuse closest to bottom right
a is opposite b is adjacent
a = 6 b = 4
area of triangle is ab over 2
6 x 4 = 24 div 2 = 12
2007-12-02 08:50:04 · answer #3 · answered by ViewtifulJoe 4 · 1⤊ 1⤋
2x-3y-12=0
2x-12=3y
3y=2x-12
y=2/3x-4
y-intercept = (0,-4)
x-intercept = 2/3x-4 = 0
4= 2/3x
x = (6,0)
distance of side A = 4
distance of side B = 6
4 x 6 x 1/2 = 4 x 3 = 12
2007-12-02 17:37:11 · answer #4 · answered by Anonymous · 0⤊ 1⤋
tinhngi is correct. Substitution of x=0 and y=0 gives points of intersection with the other axis, since that is the point when the values x and y ARE zero.
This principle is used time after time to solve equations.
It is therefore worth remembering
2007-12-02 09:07:26 · answer #5 · answered by eastanglianuk1951 3 · 0⤊ 1⤋
2x-3y-12=0 --> y=(2/3)x - 4
1/
x-intercept: p = 6 (y=0)
y-intercept: q= -4 (x=0)
2/ Area = (1/2) * IpI * IqI = 12 area units
2007-12-02 08:42:06 · answer #6 · answered by tinhnghichtlmt 3 · 2⤊ 1⤋
lol @ first answer, and, I'm afraid, totally agree!
2007-12-02 08:43:40 · answer #7 · answered by Aye. Right! 6 · 1⤊ 0⤋
mabye draw a graph?
2007-12-02 08:42:05 · answer #8 · answered by Aim High! 4 · 0⤊ 2⤋
i didn't.
2007-12-02 08:41:59 · answer #9 · answered by Anonymous · 0⤊ 0⤋