2007-12-02 07:32:40 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
As you have written (but may not mean):-
√3 x = 9
x = 9 / √3
x = 9√3 / 3
x = 3√3
You may have meant:-
√3(x + 3) - 4 = 8
√3(x + 3) = 12
(x + 3) = 12 / √3
x = 12 / √3 - 3
x = 3 (4√3 - 1)
Tip
Use brackets to avoid wasting time of those responding.
2007-12-02 10:24:56 · answer #1 · answered by Como 7 · 2⤊ 1⤋
have to square both sides first:
\/3x + 3 - 4 = 8
first combine + 3 and -4 using laws of signed numbers.
\/3x - 1 = 8
Now square both sides to clear the radical:
8*8 = 64
3x-1
3x-1
-------
9x^2 -3x
.........-3x +1
-----------------
9x^2 -6x +1 = 64
now factor:it:
9x^2 -6x + 1 -64 = 0
9x^2 -6x -63 =0
[3x - 9] [3x + 7] = 0
check your work:
3x - 9
3x +7
------
9x^2 - 27x
.........+21x -63
---------------------
9x^2 - 6x -63 = 0
2007-12-02 16:01:59 · answer #2 · answered by JUAN FRAN$$$ 7 · 1⤊ 2⤋
add 1 to each side and you get
SQR(3x) =9
square each side and you get
3x = 81
So x must equal 27.
2007-12-02 15:42:13 · answer #3 · answered by hottotrot1_usa 7 · 1⤊ 1⤋
are u sure you wrote the equation correctly? does the "square root" extend to the "+3" as well? please clarify
2007-12-02 15:40:42 · answer #4 · answered by shadowsjc 2 · 1⤊ 1⤋
No
2007-12-02 15:38:20 · answer #5 · answered by michael b 1 · 0⤊ 1⤋