A weather station releases a balloon that rises at a constant 15m/s relative to the air, but there is a wind blowing at 6.5m/s toward the west. What are the magnitude and direction of the velocity of the balloon?
What is the resulting displacement of the following series of movements: 10.0m[N65oW], 20.0m[S], 15.0m [W15oS].
2007-12-02 07:17:27 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
1.) MAG = √(15^2 + 6.5^2) = 16.348m/s
DIR = arc tan(15/6.6) = 66.571 degrees
16.348m/s up and toward the west at an angle of 66.571 degrees above the horizontal.
2.) N - S:
10cos65 - 20 - 15cos15 = -30.2627m
E - W:
10sin65 - 15sin15 = 5.18079m
MAG = √(30.2627^2 + 5.18079^2) = 30.7030m
DIR = arc tan(5.18079/30.2627)
= 9.7145degrees east of south
That is 30.7m[S9.71(degrees)E]
2007-12-05 00:12:43 · answer #1 · answered by jsardi56 7 · 0⤊ 0⤋