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f(x)=2x-3\x^2+2
Horizontal:
Vertical:

b) g(x)=5x\x-1
Horizontal:
Vertical:

2007-12-02 06:43:14 · 2 answers · asked by ViewSonic 2 in Science & Mathematics Mathematics

2 answers

Do you mean f(x) = (2x - 3)/(x^2 + 2)? Find the horizontal asymptotes by finding
lim(x->inf(f(x)) and lim(x->-inf(f(x)). Find vertical asymptotes (if any) by finding where the denominator of f(x) = 0.

Same for g(x).

2007-12-02 07:05:39 · answer #1 · answered by Tony 7 · 0 0

a million) f(x) = (2x+3)/(x+2) to locate the vertical asymptote, set the denominator to 0: x+2 = 0 x = -2 Veritcal asymptote: x = -2 to locate the horizontal asymptote: evaluate the tiers of the numerator and denominator (degree is the optimal exponent which in the two numerator and denominator is a million) considering degree are the comparable, the horizontal asymptote is the ratio of the extra advantageous coefficients: Horizontal: y = 2/a million = 2 2) g(x) = 5x/(x^2 - a million) vertical: x^2 - a million = 0 x^2 = a million x = a million, -a million vertical: x = a million, x = -a million horizontal: degree of numerator = a million degree of denominator = 2 considering degree is larger on backside, the horizontal asymptote is y = 0 horizontal: y = 0 voila

2016-12-17 04:46:35 · answer #2 · answered by Anonymous · 0 0

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