2007-12-02 06:12:44 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
| 3c + 1 | = 17:-
3c + 1 = 17
3c = 16
c = 16/3
or
3c + 1 = -17
3c = - 18
c = - 6
c = 16/3 , c = - 6
2007-12-02 06:26:24 · answer #1 · answered by Como 7 · 3⤊ 2⤋
| 3c + 1 | -4 = 13
| 3c + 1 | = 17
3c+1 = 17 --> c = 16/3
3c+1 = -17 --> c -6
2007-12-02 06:17:28 · answer #2 · answered by ironduke8159 7 · 3⤊ 1⤋
|3c+1|-4=13
|3c+1|=13+4
|3c +1|=17
3c+1=+17 or 3c+1=-17
3c+1=17
3c=18
c = 6
3c+1=-17
3c=-18
3c=-6
2007-12-02 06:20:19 · answer #3 · answered by andreea 2 · 0⤊ 3⤋
| 3c + 1 | - 4 = 13
| 3c + 1 | = 17
3c + 1 =17
3c = 16
c = 16/3
OR
3c +1 = -17
3c = -18
c = -6
2007-12-02 06:37:28 · answer #4 · answered by Wits 2 · 0⤊ 2⤋
add 4 to both sides to cancel -4 out:
I 3c+1 I = 17
b/c of absolute value, u do this:
3c+1 = -17, and 3c+1 = 17
then for both problems you subtract 1 from both sides and then divide by 3, which gives u......
c = -6 and c = 16/3
2007-12-02 06:23:44 · answer #5 · answered by Anonymous · 0⤊ 3⤋